Question

Two cities A and B are at a distance of 60 km from each
other. Two persons Pand Q.start from First city at a speed
of 10km/hr and 5km/hr respectively. Preached the second
city B and returns back and meets Q at Y. Find the distance
between A and Y.​

Answer 1

Step-by-step explanation:

P will take 6 hours (60/10) to reach B. By that time Q will cover a distance of 30 km (6*5).

again for remaining 30 km. P and Q will cover distance in the ratio of 2:1 due to difference in their speed

so P will cover (2/3) of 30 km i.e. 20 km and Q will cover 10 km.

So distance between A and Y will be 30+10 i.e. 40 km

Answer 2

Step-by-step explanation:

Time taken by P to reach city B is 6hr. In 6 hr, distance covered by Q is 30km. Now at some x distance, they will meet. So

x/5 = (30-x)/10. X= 10.

So distance b/w A and Y is 30+10 =40 km

Therefore, the distance between A and Y is 40 km.