Question

two classes conduct their charity shows with a gap of 60days and756days. if both the classes conduct the charity shows on 1st January 2004determine the minimum number of days when they will be holding the event simultaneously next time
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Answer 1

Answer:

11th April 2014

Step-by-step explanation:

the no of days after which they will held event simultaneously = LCM(60,756)

60 = 2×2×3×5 = 2²×3×5

756 = 2×2×3×3×3×7 = 2²×3³×7

LCM= 2²×3³×5×7 = 3780

So they will held the event on 11th April 2014.