two classes of 10th standard took the same test one class of 35students got an average of 48 marks and other class of 45students got an average of 32 marks the average of all the students is plz answer
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Total marks of 48 students =48x45=2160
Total marks of 48 students =48x45=2160Let the number of boys be B and the number of girls be (48−B)
Total marks of 48 students =48x45=2160Let the number of boys be B and the number of girls be (48−B)Then total marks of boys =40B
Total marks of 48 students =48x45=2160Let the number of boys be B and the number of girls be (48−B)Then total marks of boys =40BTotal marks of girls =50(48−B)=2400−50B
Total marks of 48 students =48x45=2160Let the number of boys be B and the number of girls be (48−B)Then total marks of boys =40BTotal marks of girls =50(48−B)=2400−50B⇒ 40B+2400−50B=2160
Total marks of 48 students =48x45=2160Let the number of boys be B and the number of girls be (48−B)Then total marks of boys =40BTotal marks of girls =50(48−B)=2400−50B⇒ 40B+2400−50B=2160 ⇒ 10B=240
Total marks of 48 students =48x45=2160Let the number of boys be B and the number of girls be (48−B)Then total marks of boys =40BTotal marks of girls =50(48−B)=2400−50B⇒ 40B+2400−50B=2160 ⇒ 10B=240⇒ B=24
Total marks of 48 students =48x45=2160Let the number of boys be B and the number of girls be (48−B)Then total marks of boys =40BTotal marks of girls =50(48−B)=2400−50B⇒ 40B+2400−50B=2160 ⇒ 10B=240⇒ B=24Thus number of girls =48−24=24
Total marks of 48 students =48x45=2160Let the number of boys be B and the number of girls be (48−B)Then total marks of boys =40BTotal marks of girls =50(48−B)=2400−50B⇒ 40B+2400−50B=2160 ⇒ 10B=240⇒ B=24Thus number of girls =48−24=24Therefore, required ratio =24:24=1:1
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average of all the students are 2160
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