Two classmates Salma and Anil simplified two different expressionsduring the revision
hour and explained to each other their simplifications. Salma explains simplification of
V2 / (V5 +13) and Anil explains simplification of 728 + 798 +v147 . Write both
simplifications. What value does it depict.
please tell the answer step by step
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Two classmates Salma and Anil simplified two different expressions during the revision hour and explained to each other their simplifications. Salma explains simplification of √ 2/√5 +√3 by rationalizing the denominator and Anil explains simplifications of (√2 + √3)(√2 − √3) by using the identity (a + b)(a − b). Answer the following question.
Question (1) :- 1. What is the conjugate of √5 + √3.
a) √5 + √3
b) √5 − √3
c) √5 × √3
d) √5/√3
Answer :-
we know that, to find the conjugate of binomial surds, we changes the sign in between the terms, that is,
'+' becomes '-' .
'-' becomes '+'.
therefore, the conjugate of √5 + √3 is √5 - √3 . (Option b) .
Question (2) :- By rationalizing the denominator of √ 2/√5 +√3
Salma got the answer:
a) √ 2/√5 −√3
b) √ 2(√5 −√3)/2
c) √5 − √3
d) √ 2(√5 +√3)/2
Solution :-
→ √2/(√5 + √3)
rationalizing the denominator we get,
→ {√2/(√5 + √3)} * {(√5 - √3)/(√5 - √3)}
→ {√2 * (√5 - √3)} / {(√5 + √3) * (√5 - √3)}
using (a + b)(a - b) = a² - b² in denominator now,
→ {√2 * (√5 - √3)} /{(√5)² - (√3)²}
→ {√2 * (√5 - √3)} / (5 - 3)
→ {√2 * (√5 - √3)} / 2
→ √2(√5 - √3)/2 (Option b)
Question (3) :- Anil applied _______ identity to solve (√5 + √7)(√5 − √7)
a) (a + b) (a + b)
b) (a + b) (a − b)
c) (a − b) (a − b)
d) a^2+2ab+b^2
Solution :-
→ (√5 + √7)(√5 − √7)
Let ,
√5 = a
√7 = b
then,
→ (√5 + √7)(√5 − √7) = (a + b)(a - b) (Option b) .
Question (4) :- (√2 + √3)(√2 − √3) =________
a) −1
b) 1
c) 5
d) -5
Solution :-
using (a + b)(a - b) = a² - b² we get,
→ (√2)² - (√3)²
→ 2 - 3
→ (-1) (Option a) .
Question (5) :- Addition of two irrational numbers is equal to _______.
a) Rational
b) Irrational
c) Integers
d) Whole Number
Solution :-
Addition of two irrational numbers is equal to Irrational number . (Option b).
Note :- if the irrational parts of the numbers have a zero sum (cancel each other out), the sum will be rational.