Two clay balls collide head-on in a perfectly inelastic collision. The first ball has a mass of
0.5 kg and an initial velocity of 4 m/s to the right. The second ball has a mass of 0.25 kg and an
initial velocity of 3 m/s to the left. Find the velocity of clay balls that stuck together
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Answer:
3.66ms-1
Explanation:
For inelastic collision the colliding body usually combine together and move with a common velocity. According to conservation of momentum for inelastic collision: m1u1+m2u2=(m1+m2)v
From this eq. combined velocity can be calculated.
cbduty235:
i cant see an attachment
Really Sorry, the answer is 3.66 ms-1, I also forgot to attach my solution. It’s easy, try by yourself.
Sorry again since the motion is oppositely directed formula should be m1u1-m1u2=(m1+m2)v and the answer will be : v= 1.66 ms-1 towards the right.
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