Question

Two clay balls collide head-on in a perfectly inelastic collision. The first ball has a mass of
0.5 kg and an initial velocity of 4 m/s to the right. The second ball has a mass of 0.25 kg and an
initial velocity of 3 m/s to the left. Find the velocity of clay balls that stuck together

Answer 1

Explanation:

by conservation of momentum

mv=(3+1)vf

vf=4v

loss in kinetic energy=2mv2−24m(4v)2=83mv2=43KEi

Answer 2

Answer:

a) By momentum conservation,

2(4)−4(2)=2(−2)+4(ν

2

)

⟹ν

2

=1m/s.

b) e=

Velocityofapproach

Velocityofseparation

=

4−(−2)

1−9−2)

=

6

3

=0.5

c) At the maximum deformed state, by conservation of momentum, common velocity is ν=0

J

D

=m

2

(ν−u

2

)=4[(0−(−2)]=8Ns

d) Potential energy at the maximum deformed state,

U= loss in kinetic energy during defirmation

or U=(

2

1

m

1

u

1

2

+

2

1

m

2

u

2

2

)−

2

1

(m

1

+m

2

)ν

2

=(

2

1

2(4)

2

+

2

1

4(2)

2

)−

2

1

(2+4)(0)

2

=24J

e) J

R

=m

2

(ν

2

−ν)=4(1−0)=4Ns

also J

R

=eJ

D

=0.5×8=4Ns