Question

two cliffs of heights 120m and 100.4m are separated by a horizontal distance of 16m. if a car has to reach from the first cliff to second, the horizontal velocity of the car should be

Answer 1

vertical height difference between two cars while it jump from one cliff to another cliff

$\Delta H = 120 - 100.4 = 19.6 m$

now the time taken by the car to cover this vertical displacement

$y = v_i*t + \frac{1}{2} gt^2$

$19.6 = 0 + \frac{1}{2}*9.8 * t^2$

$t = 2s$

so car can cover this displacement in 2 seconds

now the velocity of car in horizontal direction will be

$v = \frac{d}{t}$

$v = \frac{16}{2}$

$v = 8 m/s$

so speed of car will be 8 m/s

Answer 2

Answer:

answer is 8

Explanation:

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