Question

Two closed conducting loops have mutual inductance of 1H. Average e.m.f induced in one loop if current in the other changes by 2 An 1 s.
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Answer 1

Answer:

100V

Explanation:

e=Mdtdi

⇒e=0.1×0.02(20−0)=100V

Answer 2

Given: Two closed conducting loops have mutual inductance of 1 H. The current in other loop changes by 2 A in 1 s

To find: Average EMF induced

Explanation: EMF is induced when the magnetic field changes in a loop. On changing the current in other loop, the magnetic field changes and EMF is induced in other loop.

Mutual inductance (M) = 1 H

Current change (di) = 2 A

Time difference (dt) = 1 s

Let EMF induced be denoted as e.

Formula for calculating EMF is:

e= - M di/dt

= -1 * 2/1

= -2 V

The negative sign shows that direction of EMF is opposite to the current in other loop.

The average EMF induced is 2 V.