Question

Two closed cuboidal metal tanks are to
be painted from inside to avoid rusting
(Fig 14.18). If one tin of paint can paint
5000 cm' of the area, find which cuboidal
tank will require more number of tins and
by how much
first tank


l =5m
b= 1.5m
h=2m

second tank

l=5m
b=1m
h=3m​

Answer 1

Answer:

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Answer 2

tank 1

area of cuboid = 2h(l+b)

=2x2(1.5+5)

=4x6.5

= 26.0

1m=100cm

26m=2600cm

2600/5000

= 5.2/10

= 0.52------1 step

tank 2

area of cuboid = 2h(l+b)

= 2x3(1+5)

= 2x3(6)

= 6x6

= 36

1m = 3600cm

3600/5000

= 7.2/10

= 0.72

so the tank 2 required more paint

so the answer is = Tank 2 , 10 more tins

pls vote me