Two closed vessels of the equal volume contain air at 105KPa at 300K and are connected through a narrow tube. If one of the vessels is now maintained at 300K and the other at 400K then the common pressure becomes.
(A) 120kPa
(B) 150kPa
(C) 105kPa
(D) 300kPa
Answers
Answered by
1
Answer:
120 KPA
Explanation:
Correct option is A)
In this case, let the initial pressure = P and final pressure = P'. Since (P/T) = constant, considering the system of two spheres of equal volume, we get,
300
P
+
300
P
=
300
P
′
+
400
P
′
here, P = 105k Pa
Solving we get, P
′
=120kPa
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