Two co-planar, concentric circular coils of radii a and b are placed in the y-z plane such that the common center of the coils is origin (a >> b). A current i flows in the outer coil. Now the inner coil is moved along the x-axis with a constant speed v keeping its plane unchanged. The emf induced in the inner coil is maximum at:
Only answer i got for this was a satirical one lmao
Answers
Answer:induced emf e in the coil is given by, e = -(dφ/dt) , where φ is flux of magnetic field.
induced current i = e/R =begin mathsize 12px style equals space minus space 1 over R fraction numerator d phi over denominator d t end fraction end style, where R is resistance of coil
charge circulating in th coil Q = | i×dt | = dφ/R = (1/R) d( B×A) .................(1)
where B is flux density of magnetic field, A is area of coil.
magnetic field flux density B inside the coil of radius a is given by, Bbegin mathsize 12px style equals space fraction numerator mu subscript 0 space cross times space i over denominator 2 a end fraction end style
In eqn.(1), Area A is constant and by substituting for B, we get begin mathsize 12px style Q space equals space open parentheses A over R close parentheses fraction numerator mu subscript 0 over denominator 2 a end fraction d i end style............................(2)
in Eqn.(2), di is change in current 0 to i, hence we can write di = i to get charge Q
Hencebegin mathsize 12px style Q space equals space open parentheses A over R close parentheses fraction numerator mu subscript 0 over denominator 2 a end fraction cross times i end style