Question

Two coherent sources are placed 1.8cm apart. Interference fringes are obtained on screen

80cm away. The fourth bright fringe is at a distance of 1.08 cm from the central fringe.

Calculate the wavelength of the light used.​

Answer 1

Explanation:

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Answer 2

Answer:

The wavelength of light used is of 6.07×$10^{-3}$ m.

Explanation:

Step by step solution:

Step 1: Prerequisite knowledge

During the phenomena of interference, the formation of bright and dark fringes occurs.

The distance of the bright fringes from the central fringe is given by :

$y=\frac{nD\lambda}{d}$

where, n is the number of fringes.

Step 2: Given information

y = 1.08 cm

d = 80 cm

D = 1.8 cm

n = 4

Step 3: Calculation of wavelength

$y=\frac{nD\lambda}{d}$

putting values in the equation, we get

$1.08=\frac{(4)(\lambda)(80)}{1.8}$

$\lambda=6.07$×$10^{-3} cm$