Question

Two coherent sources of same intensity and 25 MHz frequency are at equal distance from a point. The resultant intensity at the point is 1,- The point is moved
in such a manner that its distance from one source is 3 m more than its distance from the other source. What will be the new intensity at this point?
A. O 1.5 1.
B. O 0.51
C. 3.518
D. OSIR​

Answer 1

Answer:

3.518

Explanation:

i don't know the explanation

Answer 2

Answer: The answer is (D) 0.

When two coherent sources of the same intensity and frequency are at an equal distance from a point, the resultant intensity at that point is maximum and given by 4I0, where I0 is the intensity of each source.

Explanation:

Let's assume the distance of the point from each source is d. Then, the path difference between the two waves reaching the point is given by δ = dλ/D, where D is the distance between the sources and λ is the wavelength of the waves.

As the sources have the same frequency, the wavelength is constant. Hence, δ is directly proportional to the distance between the sources. Therefore, when the distance of the point from one source is 3 m more than its distance from the other source, the path difference becomes 3λ/D more than its original value.

Now, the phase difference between the waves is given by 2πδ/λ. When the phase difference is an odd multiple of π, destructive interference occurs, and the intensity at the point is zero.

Thus, the new intensity at the point will be zero. Therefore, the answer is (D) 0.

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