Question

Two coherent sources, whose intensity ratio is 81 : 1 produce interference fringes. Calculate the ratio of intensity of maxima and minima in the fringe system.
(Ans. : 25 : 16)

Answer 1

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⭐Actually welcome to the WORLD OF WAVE OPTICS .....

⭐Basically we know that ....

⭐Intensity of a wave is directly proportional to the Square of the Amplitude of the Wave ...

⭐so after solving we get...

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Answer 2

Answer:

Concept :

Interference fringes are created by the interference phenomena that occurs in waves. The electric field vectors of the waves sum in the locations where two of the light waves overlap. The interference between light waves with the same polarisation might be positive or negative. Waves with constructive interference are in phase with one another, while waves with destructive interference are 180 degrees apart. For the interference to remain stable over time, waves must also preserve their phase connection and be coherent.

Explanation:

$\frac{I_{max}}{I_{min}}$ = $\left ( \frac{\sqrt{\sqrt{I_{1}} + \sqrt{I_{2}}}} {\sqrt{I_{1}- \sqrt{I_{2}}}} \right )$

       = $\left (\frac{\sqrt{81{} + 1}}{\sqrt{81{} - 1}} \right )^{2}$

        =$\frac{100}{64}$

       = $\frac{25}{16}$

       = 25 : 16

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