two coils A and B of 600 and 100 turns respectively are wounded uniformly around a wooden ring haveing a mean circumference of 30cm the cross sectional area of the ring is 4 cm^2 calculate .a) themutual inductance of the coil .b) the emf induced in coil B when a current of 2A is coil A is reverse in 0.001 second
Answers
Two coils having 30 and 600 turns respectively are wound side-by-side on a closed iron circuit of area of cross-section 100 sq.cm. and mean length 200 cm. Estimate the mutual inductance between the coils if the relative permeability of the iron is 2000. If a current of zero ampere grows to 20 A in a time of 0.02 second in the first coil, find the e.m.f. induced in the second coilRead more on Sarthaks.com - https://www.sarthaks.com/492125/coils-having-turns-respectively-are-wound-side-side-closed-iron-circuit-area-cross-section
Explanation:
Formula used : M = N1N2/(l/μ0μrA)H, N1 = 30, N2 = 600; A = 100 x 10-4 = 10-2m2, l = 2m ∴ M = μ0μr A N1N2/l = 4π × 10−7 × 2000 × 10−2 × 30 × 600/2 = 0.226 H dI1 = 20 − 0 = 20 A; dt = 0.02 s;Read more on Sarthaks.com - https://www.sarthaks.com/492125/coils-having-turns-respectively-are-wound-side-side-closed-iron-circuit-area-cross-section