Physics, asked by abratmughal4262, 1 year ago

Two coils a of 12500 turns and b of 16000 turns lie in a parallel place so that 60./. Of flux produce in a link with b it is found that a current of 5 A in a product a flux of. 6 m Wb while the same current in b produce. 8mWb the mutual induction of 2 coils is

Answers

Answered by jefferson7
7

Two coils a of 12500 turns and b of 16000 turns lie in a parallel place so that 60./. Of flux produce in a link with b it is found that a current of 5 A in a product a flux of. 6 m Wb while the same current in b produce. 8mWb the mutual induction of 2 coils is

Explanation:

Flux/ampere  in A  = 0.6 /  5

=0.02mWb

Flux linked with B = 0.12 * 6  = 0.072 mWb

M= 0.072* 10⁻³ * 16,000

= 1.15H

Now,

L₁ = 12,500   * 0.6 / 5    

=150 * 10⁻³ H

L₂  = 16,000 * 0.8 / 5

=256*10⁻³

k = M/√L₁L₂

= 1.15/√1.5*256

=0.586

Answered by goyalmridul2021
0

Explanation:

hope it helps..answer will be M=1.152 henry

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