Question

two coils have an effective resistance 16ohm when connected in series and 3.75 ohm when connected in parallel. find individual resistance​

Answer 1

Answer:

individual resistance in 10.2

Explanation:

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Answer 2

Answer :

The individual resistance of the two coils is R1 = 8 ohm and R2 = 8 ohm.

Explanation :

Let's call the resistance of the first coil R1 and the resistance of the second coil R2.

When the two coils are connected in series, the effective resistance is 16 ohm:

R1 + R2 = 16 ohm

When the two coils are connected in parallel, the effective resistance is 3.75 ohm:

1/R = 1/R1 + 1/R2

From the first equation, we can solve for the value of R1:

R1 = 16 ohm - R2

Substituting this into the second equation, we get:

1/R = 1/(16 ohm - R2) + 1/R2

Solving for R2, we get:

R2 = 8 ohm

And using this value, we can find the value of R1:

R1 = 16 ohm - R2 = 16 ohm - 8 ohm = 8 ohm

So the individual resistance of the two coils is R1 = 8 ohm and R2 = 8 ohm.

To know more about the concept please go through the links :

https://brainly.in/question/8306325

https://brainly.in/question/6216308

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