Question

Two coils of resistance Ri = 32 and R=922 are connected in series across a battery
of potential difference 14 V.
(1) Draw the circuit diagram
(li) Calculate current in the circuit
(IT) Find the electrical energy consumed in 1 min in resistance. Ri
(iv) Find the electrical energy consumed in 1 min in resistance R2-
(v) Find the energy dissipated per unit time in the circuit​

Answer 1

Explanation:

ANSWER

When 8 and 12 are in parallel

and 7.2 is in series with them

Net Resistance

10

7.2

+

12+8

8×12

=

10

72

+

20

96

=

10

72

+

10

48

=

10

120

=12Ω

Total current =

netR

V

=

12

6

=0.5Ω

Voltage across R

1

=iR

1

=0.5×7.2

=3.6

solution

Answered By

toppr

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