Two coils of turns N1 and N2 having current I1 and I2 of length L are coupled on same core having radius r1 and r2 find
the expression for mutual inductance between the coils.
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Explanation:
coil B kept near another coil A has magnetic flux passing through it when kept near coil A. The ratio of magnetic flux through the coil B to the current in the coil A is called as mutual inductance of coil A and coil B.
M
12
=
i
ϕ
2
Let S
1
carries a current i.
Magnetic field inside S
1
will be B=μ
o
N
1
i/l
Flux through each turn of S
2
is ϕ=B×πr
2
2
ϕ=μ
o
N
1
πr
2
2
i/l
Flux through all turns of S
2
is ϕ
B
=ϕN
2
ϕ
B
=μ
o
N
1
πr
2
2
iN
2
/l
M=
i
ϕ
B
=
l
μ
o
N
1
N
2
πr
2
2
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