Two coin are tossed. find the probability.
Answers
Answer:so the probability is (H,H),(H,T),(T,H),(T,H)
probability of getting heads or either sides is 3/4
probability of getting tails or either sides is 3/4
probability of getting only heads is 1/4
probability of getting only tails is 1/4
probability of getting only one head is 2/4=>1/2
probability of getting only one tail is 2/4=>1/2
Step-by-step explanation:
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Answer:
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Explanation:
When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails)
i.e., (H, H) or (H, T) or (T, T).
Therefore, total numbers of outcome are 2² = 4.
Find the probability of:
(i) getting two heads
(ii) getting two tails
(iii) getting one tail
(iv) getting no head
(v) getting no tail
(vi) getting at least 1 head
(vii) getting at least 1 tail
(viii) getting atmost 1 tail
(ix) getting 1 head and 1 tail
Solution:
(H , H) (H , T) (T , H) (T , T)
(i) P(getting 2 heads) = 1/4.
(ii) P(getting 2 tails) = 1/4.
(iii) P(getting 1 tail) = 2/4 = 1/2.
(iv) P(getting no head) = 1/4.
(v) P(getting no tail) = 1/4.
(vi) P(getting at least 1 head) = 3/4.
(vii) P(getting at least 1 tail) = 3/4.
(viii) P(getting atmost 1 tail) = 3/4.
(ix) P(getting 1 head and 1 tail) = 2/4 = 1/2.