Math, asked by Ashwinimali2003, 2 months ago

Two coin are tossed. find the probability.​

Answers

Answered by taeaiyana
1

Answer:so the probability is (H,H),(H,T),(T,H),(T,H)

probability of getting heads or either sides is 3/4

probability of getting tails or either sides is 3/4

probability of getting only heads is 1/4

probability of getting only tails is 1/4

probability of getting only one head is 2/4=>1/2

probability of getting only one tail is 2/4=>1/2

Step-by-step explanation:

hope this info helps you

Answered by NaturalStarNehru
1

Answer:

Please mark me as Brilliant

Explanation:

When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails)

i.e., (H, H) or (H, T) or (T, T).

Therefore, total numbers of outcome are 2² = 4.

Find the probability of:

(i) getting two heads

(ii) getting two tails

(iii) getting one tail

(iv) getting no head

(v) getting no tail

(vi) getting at least 1 head

(vii) getting at least 1 tail

(viii) getting atmost 1 tail

(ix) getting 1 head and 1 tail

Solution:

(H , H) (H , T) (T , H) (T , T)

(i) P(getting 2 heads) = 1/4.

(ii) P(getting 2 tails) = 1/4.

(iii) P(getting 1 tail) = 2/4 = 1/2.

(iv) P(getting no head) = 1/4.

(v) P(getting no tail) = 1/4.

(vi) P(getting at least 1 head) = 3/4.

(vii) P(getting at least 1 tail) = 3/4.

(viii) P(getting atmost 1 tail) = 3/4.

(ix) P(getting 1 head and 1 tail) = 2/4 = 1/2.

Similar questions