Two coin are tossed together. Find probability of getting
1) at least one tail
2)one head and one tail
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2
Total number of outcomes = 4
1) The number of favorable outcomes = 3 P(atleast one tail) = No.of favorable outcome/
Total number of outcomes
=3/4
2) The number of favorable outcomes = 2
P(1 head and 1 tail)=No.of favorable outcome/
Total number of outcomes
=2/4
=1/2
dimonddartfield:
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Answered by
3
Answer:
1) 3/4
2) 1/2
Total outcomes are HH, TT, HT, TH
P( at least one head) =3/4
P(one head and one tail) =2/4=1/2
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