two coin are tossedat the same time what is the probability of getting at least one head [hint p ( at least one ahead)= 1 -p( no head
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3/4
Step-by-step explanation:
possibilities are (H,T),(T, H),(H,H),(T,T)
at least one head (H,T),(T,H),(H,H)
so the probability is 3/4
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