Two coin tossed simunteniously find probability of getting exactly one
head
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Answered by
3
_solution:_
Possible outcomes= HH,HT,TH,TT
where H =heads and T= tail
Total no. of outcomes = 4(2 heads and 2 tails)
No. of favourable outcomes= 2 (HT/TH)
Required probability =no. of fav. outcomes/total no. of outcomes
=2/4
=1/2
Possible outcomes= HH,HT,TH,TT
where H =heads and T= tail
Total no. of outcomes = 4(2 heads and 2 tails)
No. of favourable outcomes= 2 (HT/TH)
Required probability =no. of fav. outcomes/total no. of outcomes
=2/4
=1/2
Answered by
5
When two coins are tossed simulteniously .
Then, all possible outcomes are
HH , HT , TH and TT
Total number of outcomes = 4
•°• Probability of getting exactly one head = 1/4
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