Question

Two coins are tossed
1 point
simultaneously. What is
the probability of getting
atleast one tail? *
O (A) 3/4
O (B) 1/2
O (C) 1/4
O (D) 2/3​

Answer 1

Answer:

The answer for this question is b)1/2

Answer 2

Answer:

mate option A is right answer plzz mark me as brainlist

Step-by-step explanation:

E7 = {TH, HT, TT} and, therefore, n(E7) = 3.

Therefore, P(getting at least 1 tail) = P(E2) = n(E2)/n(S) = ¾.