Question

two coins are tossed 1000 and outcome are recorded as below based on this information the probability of almost one head is​

Answer 1

Answer:

p(H)=550/1000=0.55

Step-by-step explanation:

no .of favourable outcomes=550

total no .of outcomes=1000

p(H)=550/1000=0.55

Answer 2

Answer:

TOTAL 1000

FREQUENCY OF 1 HEAD IS 550

PROBABLITY FOR ONE HEAD = FREQUENCY OF 1 HEAD÷ TOTAL NO OF COIN TOSSED.

= 550÷1000

=11/20

ANS = 11/20

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