two coins are tossed 1000 and outcome are recorded as below based on this information the probability of almost one head is
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Answered by
3
Answer:
p(H)=550/1000=0.55
Step-by-step explanation:
no .of favourable outcomes=550
total no .of outcomes=1000
p(H)=550/1000=0.55
Answered by
7
Answer:
TOTAL 1000
FREQUENCY OF 1 HEAD IS 550
PROBABLITY FOR ONE HEAD = FREQUENCY OF 1 HEAD÷ TOTAL NO OF COIN TOSSED.
= 550÷1000
=11/20
ANS = 11/20
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