Question

Two coins are tossed 1000 times and the outcomes are recorded as below. Based on this information, the probability for at most one head is​

Answer 1

Answer:

4/5

Step-by-step explanation:

As, our Favorable Outcomes are at most head here, we can either have 0 head or 1 head. [since, atmost 1 means ≤1]

Here, Favorable Outcomes = 550 + 250 = 800

And, Total Outcomes = 1000

Probability(Event) = Favorable Outcomes/Total Outcomes

$Probability(Event) = \frac{800}{1000} = \frac{8}{10} = \frac{4}{5}$

Therefore, required probability = 4/5