Two coins are tossed 200 times and the outcomes are recorded as HH - 56, TH/HT- 110, TT-34. Probability of occurrence of atleast one Head is
0.33
0.43
0.63
0.83
give explanations
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0
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Answered by
2
Answer:
0.83
Step-by-step explanation:
In the question they asked for atleast one head
so, HT+HH= 110 + 56 = 166
then, Probability(getting heads) = no. of outcomes / no. of tatal trial
= 166/200
= 0.83
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