Math, asked by saikatmandal15398, 6 months ago

Two coins are tossed 200 times and the outcomes are recorded as HH - 56, TH/HT- 110, TT-34. Probability of occurrence of atleast one Head is



0.33

0.43

0.63

0.83
give explanations

Answers

Answered by sannvi2010
0

Answer:

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Answered by mohammad14010
2

Answer:

0.83

Step-by-step explanation:

In the question they asked for atleast one head

so, HT+HH= 110 + 56 = 166

then, Probability(getting heads) = no. of outcomes / no. of tatal trial

= 166/200

= 0.83

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