Question

Two coins are tossed 400 times, we get:
Two heads: 128 times, One head: 160 times; No
head: 112 times when two coins are tossed at
random, what is the probability of getting,
(i) 2 heads (ii) 1 head (iii) 0 head? answer​

Answer 1

Step-by-step explanation:

(i) P(getting 2 head):- 128÷400 =8/25

(ii) P(getting 1 head ):- 160÷400 = 2/5

(iii) P(getting 0 head ):- 112÷400 = 7/25.

HOPE IT HELPS YOU

Answer 2

(1) total outcomes is 400*2 = 800
P(E) = 128/800 = 0.16
(2) P(E) = 160/800 = 0.2
(3) P(E) = 112/800 = 0.14

So your answer is done
I would like to inform you that find the answer in decimals in probability because in boards they will not give full marks if u find in fraction
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