Question

Two coins are tossed. Find the probability of getting (1) Both heads (2) exactly one head​

Answer 1

Answer- The above question is from the chapter 'Probability'.

Probability- It is the branch of mathematics with deals with the events and tell how likely they occur.

Formula of probability: Favourable outcomes ÷ Total number of outcomes

Given question: Two coins are tossed. Find the probability of getting

(1) both heads

(2) exactly one head​

Solution: When two coins are tossed, total number of possible outcomes =  2² = 4

Sample Space = HH, HT, TH and TT

(1) Favourable outcomes = 1

Probability (Both heads) = Favourable outcomes ÷ Total number of outcomes

                                           = $\frac{1}{4}$

(2) Favourable outcomes = 2

Probability (Exactly one head) = Favourable outcomes ÷ Total number of outcomes

                                                     = $\frac{2}{4}$

                                                     = $\frac{1}{2}$

Answer 2

_________________________________

$\huge\tt{GIVEN:}$

• Two coins are tossed.

_________________________________

$\huge\tt{TO~FIND:}$

• The probability of getting :

1. Both Heads
2. Exactly one head

_________________________________

$\huge\tt{CONCEPT~USED:}$

• Probability = The number of ways of achieving success. the total number of possible outcomes.
• Formulae = Favorable outcomes / Total number of outcomes

_________________________________

$\huge\tt{SOLUTION:}$

When two different coins are tossed randomly, the sample space is given by :

S = {HH, HT, TH, TT}

The possible outcome may be = 2² or 4

Therefore, n(S) = 4.

Now, the question is ......

_________________________________

(i) Both Heads:

↪ Probability = Favorable outcomes/ Total outcomes

↪ Probability of Getting both Heads = ¼

(ii) Exactly one Head :

↪ Probability = Favorable outcomes/ Total outcomes

↪ Probability of Getting exactly one Head = 2/4 or ½

_________________________________