Question

two coins are tossed . Find the probability of getting at most 2 heads?​

Answer 1

Answer:

Let E1 = event of getting 2 heads. Then, E1 = {HH} and, therefore, n(E1) = 1. Therefore, P(getting 2 heads) = P(E1) = n(E1)/n(S) = 1/4.

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Answer 2

Answer:

1/4 as sample space are (h,t) (h,h )( t,h) and (t,t)

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