two coins are tossed once. find the probability of getting at least one head or at most one tail.. please send it with explanation as soon as possible..
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see the experiment is two coins are tossed
so the sample space will be
{HH,HT,th,TT,}
therefore n(s)=4
event a is get at least one head
therefore
A={HH,HT,th}
n(A)=3
therefore probability of A is n(A)/n(S)
=3/4
i.e 0.75
or
75 %
event B is get at least one tail again
the n(B)is 3
so p(B) is also
3/4,0.75,75%
so the sample space will be
{HH,HT,th,TT,}
therefore n(s)=4
event a is get at least one head
therefore
A={HH,HT,th}
n(A)=3
therefore probability of A is n(A)/n(S)
=3/4
i.e 0.75
or
75 %
event B is get at least one tail again
the n(B)is 3
so p(B) is also
3/4,0.75,75%
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