Question

Two coins are tossed simulaneously 500 ,if we get to head hundred times one head 270 tines and no head 130 times then find the probability of getting one or more then one head?

Answer 1

Answer:

Step-by-step explanation:

LET E1 BE EVENT OF TWO HEADS COMING

LET E2 BE EVENT OF ONE HEAD COMING

LET E3 BE EVENT OF NO HEADS COMING

P(TWO HEADS) =P(E1) =100/500=1/5

P(ONE HEAD) =P(E2) =270/500=27/50

P(NO HEAD) =P(E3)=130/500=13/50

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Answer 2

27/50 .......,........ please mark brainliest