Question

Two coins are tossed simultaneously 200 times and we get
two heads: 58 times; one head: 83 times; 0 head: 59 times.
When two coins are tossed at random, what is the probability of getting (i) 2 heads,
(ii) 1 head, (iii) O head?​

Answer 1

Answer:

Answer are follows::---

Step-by-step explanation:

• Total number of trials = 200
• Number of times 2 heads are obtained = 58 Number of times one head is obtained = 83
• Number of times no head is obtained = 59 (i) Probability of getting 2 heads = (Number of times 2 heads have been obtained)/ (total number of trials) = (58/200) [divide both numerator and denominator by 2] = (29/100) (ii) Probability of getting 1 heads = (Number of times 1 heads have been obtained)/ (total number of trials) = (83/200) (iii) Probability of getting 0 heads = (Number of times head has not been obtained)/ (total number of trials) = (59/200)