Two coins are tossed simultaneously 500 times, following, are the outcomes:No head =100 One head =200 times Two heads =200 Times If the coins are simultaneously tossed again, compute the probability of obtaining (i) one head (i) two heads
Amir93345:
please clearly i don't understand
Answers
Answered by
31
Probability of one head from the data given is ![\frac{200}{500}=\frac{2}{5} \frac{200}{500}=\frac{2}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B200%7D%7B500%7D%3D%5Cfrac%7B2%7D%7B5%7D)
Same for two heads.
Same for two heads.
Answered by
43
No: of times one head came = 200
No: of times two heads came = 200
No: of times no head came = 100
Total no: of times the coins were tossed = 200+200+100 = 500 times
![Probability = \frac{Number. of. times . it . occurred }{Total. number . of . outcomes} Probability = \frac{Number. of. times . it . occurred }{Total. number . of . outcomes}](https://tex.z-dn.net/?f=Probability+%3D+%5Cfrac%7BNumber.+of.+times+.+it+.+occurred+%7D%7BTotal.+number+.+of+.+outcomes%7D+)
Probability that one head came =![\frac{100}{500} = \frac{1}{5} \frac{100}{500} = \frac{1}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B100%7D%7B500%7D++%3D++%5Cfrac%7B1%7D%7B5%7D++)
Probability that two heads came =
No: of times two heads came = 200
No: of times no head came = 100
Total no: of times the coins were tossed = 200+200+100 = 500 times
Probability that one head came =
Probability that two heads came =
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