Question

Two coins are tossed simultaneously 500 times. If we get 2 heads 100 times, one head 270times and no heads 130 times then find the probability of getting one or more than one head

Answer 1

number of times coin tossed=500

2 heads=100 times

1 head=270 times

no head=130 times

probability of getting one or more than one head

probability(E)=number of event/total number of event

it means

270+100/500

370/500

37/50 probability of getting one or more than one head

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Answer 2

Our required probability is 0.94.

Step-by-step explanation:

Since we have given that

Number of times 2 head occurs = 100

Number of times 1 head occur = 270

Number of times no head occur = 130

So, Probability of getting one or more than one head is given by

P(2 heads)  +  P(one head)

$\dfrac{200}{500}+\dfrac{270}{500}\\\\=\dfrac{470}{500}\\\\=0.94$

Hence, our required probability is 0.94.

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Two coins are tossed simultaneously 500 times. If we get two heads hundred times one head 270 times and no heads 130 times, then find the probability of getting one or more than one head

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