Math, asked by ramescorp, 4 months ago

two coins are tossed simultaneously 500 times. if we get two heads 100 times,one head 270 times and no head 130 times, then find the probability of getting one or more than one head

Answers

Answered by notorious09

ANSWER

Given

Totalnumberoftimes2coinsaretossed=500

Nooftimes2Headscomesup=95

Nooftimes1Tailcomesup=290

NooftimesNoHeadcomesup=115

Probabilityof2Headscomingup=

Totalnumberoftimes2coinsaretossed

Frequencyof2Headscomingup

500

=0.19

Probabilityof1Tailcomingup=

Totalnumberoftimes2coinsaretossed

Frequencyof1Tailcomingup

500

290

=0.58

ProbabilityofNoHeadscomingup=

Totalnumberoftimes2coinsaretossed

FrequencyofNoHeadscomingup

500

115

=0.23

hope it helps

Answered by bhumikabehera16

Step-by-step explanation:

NO OF TIME'S COINS TOSSED=500

2 heads= 100

1 head = 270

no head= 130

PROBABILITY OF GETTING ONE OR MORE THAN ONE HEAD

probability (E) = no. of event/ total no. of event.

it means ,.

270+100/500

370/500

37/50.. is the probability of getting one or more than one head..

HOPE THIS WILL HELPS U MATE ✌️

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two coins are tossed simultaneously 500 times. if we get two heads 100 times,one head 270 times and no head 130 times, then find the probability of getting one or more than one head​

Answers

20 TX= Ïẞ..❤️❤️❤️

two coins are tossed simultaneously 500 times. if we get two heads 100 times,one head 270 times and no head 130 times, then find the probability of getting one or more than one head