Question

Two coins are tossed simultaneously 500 times,we get
two heads = 105 times
1 head = 275 times
no head = 120 times
Find the probability of occurrence of each of these events

Answer 1

It's so easy question

Answer 2

Given,

Two coins are tossed simultaneously for = 500 times

Number of times two heads occurred = 105

Number of times one head occurred = 275

Number of times no head occurred = 120

To find,

The probability of occurrence of each of these events.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically, the probability (P) of a favorable event (E) can be calculated as;

Probability of event E

= P (E)

= (Number of times of occurrence of the favorable event) / (Total number of trials or occurrence of both favorable and unfavorable events)

As per the question,

Total number of trials

= Number of times the two coins are tossed simultaneously for

= 500

Now,

Probability (Number of times two heads occurred)

= (Number of times two heads occurred) / (Total number of trials)

= 105/500 = 0.21

=> Probability (Number of times two heads occurred) = 0.21

Now,

Probability (Number of times one head occurred)

= (Number of times one head occurred) / (Total number of trials)

= 275/500 = 0.55

=> Probability (Number of times one head occurred) = 0.55

Now,

Probability (Number of times no head occurred)

= (Number of times no head occurred) / (Total number of trials)

= 120/500 = 0.24

=> Probability (Number of times two heads occurred) = 0.24

Hence, the probability of occurrence of each of these events is 0.21, 0.55 and 0.24, respectively.