Question

Two coins are tossed simultaneously 600 times to get heads:234times,head :206 times, 0 head :160 times. If two coins are tossed at random, what is the probability of getting at least one head

Answer 1

Answer:

Solution :

Total number of tosses = 600.

Number of times we get 1 head or 2 heads = (234 + 206) = 440 .

Required probability = 440/600

                                    =11/15

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Answer 2

Answer: Probability of at least one head is 11/15

Step-by-step explanation:

Total number of tosses = 600

Number of heads appearing             Number of tosses

      2                                                               234

      1                                                                206

      0                                                                160        

At least one head  ⇒ One head or two head

Probability of at least one head = Probability of one head + Probability of two heads

Probability of at least one head  $= \frac{206}{600} + \frac{234}{600}$

Probability of at least one head  $= \frac{440}{600}$  

Probability of at least one head  $= \frac{11}{15}$

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