Two coins are tossed simultaneously. fill in the blanks. A probability of getting one tail is _
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Answer:
P(E) = 3/4
Step-by-step explanation:
no. of events= 4 (HH, HT, TH, TT)
chance of getting 1 tail = 3 ( HT, TH, TT)
here, H= head &
T= tail.
P(E)= chance of getting 1 tail/ no. of events
= 3/4.
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