Question

two coins are tossed simultaneously. find the probability that either exactly two heads or atleast one tail turn up​

Answer 1

hey buddy

here is ur answer !!

Sample space S={HH,HT,TH,TT}∴n(S)=4

Let, A be the event of getting exactly two heads.

Then A={HH} and n(A)=1

∴P(A)= n(S) /n(A) = 4/1

Let, B be the event of getting atleast one tail.

Then B={HT,TH,TT} and n(B)=3

∴P(B)= n(S) /n(B) = 4/3

Now, the events A and B are mutually exclusive.

∴P(A∪B)=P(A)+P(B)(∵ addition rule of probability)

P(A∪B)= 4/1+ 4/3=1

∴ the probability of getting exactly two heads or at least one tail is 1.

Hope it helps you ❤️....