Math, asked by dakshfoujdar096, 9 months ago

two coins are tossed simultaneously. find the probability of getting a prime number.​

Answers

Answered by Anonymous
0

Answer:

When two different coins are tossed simultaneously, the sample space is given by

S={HH,HT,TH,TT}

Therefore, n(S)=4.

(1) Getting two heads:

Let E

1

be an event of getting 2 heads.

Then, E

1

={HH} and, therefore, n(E

1

)=1.

Therefore, P(getting 2 heads) =P(E

1

)=

n(S)

n(E

1

)

=

4

1

.

(2) Getting one tail:

Let E

2

= event of getting 1 tail. Then,

E

2

={TH,HT} and, therefore, n(E

2

)=2.

Therefore, P(getting 1 tail) =P(E

2

)=

n(S)

n(E

2

)

=

4

2

=0.5

(3) Getting no tail:

Let E

3

= event of getting no tail. Then,

E

3

={HH} and, therefore, n(E

3

)=1.

Therefore, P(getting no tail) =P(E

3

)=

n(S)

n(E

3

)

=

4

1

Answer By

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Toppr

Step-by-step explanation:

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