two coins are tossed simultaneously. find the probability of getting a prime number.
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Answer:
When two different coins are tossed simultaneously, the sample space is given by
S={HH,HT,TH,TT}
Therefore, n(S)=4.
(1) Getting two heads:
Let E
1
be an event of getting 2 heads.
Then, E
1
={HH} and, therefore, n(E
1
)=1.
Therefore, P(getting 2 heads) =P(E
1
)=
n(S)
n(E
1
)
=
4
1
.
(2) Getting one tail:
Let E
2
= event of getting 1 tail. Then,
E
2
={TH,HT} and, therefore, n(E
2
)=2.
Therefore, P(getting 1 tail) =P(E
2
)=
n(S)
n(E
2
)
=
4
2
=0.5
(3) Getting no tail:
Let E
3
= event of getting no tail. Then,
E
3
={HH} and, therefore, n(E
3
)=1.
Therefore, P(getting no tail) =P(E
3
)=
n(S)
n(E
3
)
=
4
1
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Toppr
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