Question

Two coins are tossed simultaneously. Find the probability of getting at least one head​

Answer 1

$\Large{\underbrace{\underline{\bf{QUESTION\:}}}}:$

Two coins are tossed simultaneously. Find the probability of getting at least one head.

$\Large{\underbrace{\underline{\bf{ANSWER\:}}}}:$

${\bf{Given\::}}$

• Two coins are tossed simultaneously.

$\\ {\bf{To\: Find\::}}$

• The probability of getting at least one head.

$\\ {\bf{Solution\::}}$

✯ When two coins are tossed the outcomes are ⇓⇓⇓

⠀⠀⠀⠀⠀⠀ {HH, HT, TH, TT}

Therefore,

➛ Total number of outcomes = 4

☛ We have to find the probability of getting at least one head.

★ Thus, there are three cases that can be possible that are ⇓⇓⇓

⠀⠀⠀⠀⠀⠀⠀ ⠀{HH, HT, TH}

Therefore,

➛ No. of favourable outcomes = 3

As we know that,

$\orange\bigstar\:{\huge\mid}\:\bf\purple{Probability\:=\:\dfrac{No.\:of\: favourable\: outcomes}{Total\:no.\:of\: outcomes}\:}\:{\huge\mid}\:\green\bigstar$

➳ P(at least one head) = $\rm\pink{\dfrac{3}{4}}$

Answer 2

Given

• Two coins are tossed simultaneously

To find

• Probability of getting at least one head

Solution

When, two coins are tossed simultaneously, the favourable outcomes are,

• {Head, Head} , {Tail, Tail} , {Head, Tail} , {Tail, Head}

Now, probability of getting at least one head will be,

• {Head, Tail} , {Head, Head}, {Tail, Head}

Since, in every outcome, there is at least one head.

Now, we know,

• Probability = Number of favourable outcomes / Total number of outcomes

Number of favourable outcomes = 3

Total number of outcomes = 4

• P(one head) = 3/4

Hence, the probability of getting at least one head when two coins are tossed simultaneously is 3/4.