Question

two coins are tossed simultaneously. find the probability of getting (1)one head (2)two heads (3)at least one head (4)no head ​

Answer 1

Answer:

2/4

4/4

1/4

0/4

Step-by-step explanation:

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Answer 2

Answer:  1. =    1/2      2. =   1/2   3. =   3/4     4.=  0

Step-by-step explanation:    there are two coins...

 since,  total no.  of   event =  04

 a/q  

       (1)            favourable  event =   one head

                                                     =   02

   hence  =    probability of getting  one head  (p1)

=   favourable  event / total event

=       02/04

=    1/2

 

(2)         (E2)  =       getting two heads=    1

      probability  of getting   two  heads  =      favourable event / total event

                                                                  =       1/4

(3)      E3    =    getting at least one head  =   3

            (p3) =     probability of getting  at least one head  =    3/4

(4)       E4 =   gettng    0 heads  =  0

    p4  =      0/4

           = 0