two coins are tossed simultaneously. find the probability of getting the following outcome. i. two tails . ii. no tail. iii. At least one tail.
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Three coins are tossed.
We will denote H- Head; T- Tail
The possible outcomes (Exhaustive cases)are 8 as follows:
HHT, HTH, HHH, HTT
THT, TTH, THH, TTT
Atleast two tails amount to saying 2 or 3 tails.
The corresponding favourable cases are four as follows:
HTT, THT, TTH, TTT
We know that Probability
= favourable cases/ Exhaustive cases
= 4/8 = 1/2 = 0.5
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