Two coins are tossed simultaneously. Find the probability of getting (i) exactly one head (ii) at least one tail (iii) no tail
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When two coins are tossed the results are (HH,HT,TH,TT)
Total no. of outcomes =4
(i) Exactly one head = only two cases are (HT,TH)
= 2/4
=1/2
(ii) At least one tail = There are three cases (HT,TH,TT)
=3/4
(iii) No. tail = only one case (HH) =1/4
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