Question

two coins are tossed simultaneously find the probaility of getting at most one tail. exactly two heads​

Answer 1

Answer:

sample space for two coin tossed

s=(HH,HT,TT,TH)

n(s)=4

let A be the event of getting at most one tail.

A=(HT,TH)

n(A)=2

p(A)=2/4

p(A)=1/2

let O be the event of getting exactly two heads.

O=(HH)

n(O)=1

P(O)=1/4

THAT'S IT.

Answer 2

Answer:

1

Step-by-step explanation:

( HH,HT,TH,TT)

n(s)4

let A be the event of getting at most one tail

n(a) 3 (HT,TH,TT)

n(p)= n(a)/n(s)

3/4

let B be the event of getting exactly two Head

n(s)= 4

n(a)= 1

n[p] n(a) /n(s)

1/4