Math, asked by anshpndt009, 7 months ago

Two coins are tossed simultaneously. The probability of getting atmost one head is .

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Answered by vikaskumarverma

Answer:

Then, E9 = {HT, TH } and, therefore, n(E9) = 2. Therefore, P(getting 1 head and 1 tail) = P(E9) = n(E9)/n(S)= 2/4 = 1/2. The solved examples involving probability of tossing two coins will help us to practice different questions provided in the sheets for flipping 2 coins.

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