Question

two coins are tossed simultaneously then the probability of getting no head is A/B,then (A+B)^2 is equal to

Answer 1

Answer:

25

Step-by-step explanation:

HERE IS YOURS SOLUTION;

◆ When Two coins are tossed simultaneously, all the probability of getting any results are:

TT , HH , HT , TH. = 4

【 Here, T is Tail & H is Head 】

So, the probability of getting no head when two coins are tossed simultaneously are;

Probability = Favourable Outcomes ÷ Total Outcomes

TT ÷ TT + HH + HT + TH = Probability

=> 1/4 = Probability.

So, A is 1 and B is 4.

(A+B)^2=(1+4)^2

=5^2

=25

Answer 2

Answer:

probability of getting no head =a/b =1/2

ATQ. (A+B)^2=(1+2)^2=3^2=9

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