Two coins are tossed simultaneously.what is the probability one head one tail
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Observations: (H,H),(H,T),(T,H),(T,T)
Total no. of observations: 4
P(E) =
(No. of favourable outcomes)/(Total no. of observations)
= 2/4
= 1/2
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Total no. of observations: 4
P(E) =
(No. of favourable outcomes)/(Total no. of observations)
= 2/4
= 1/2
If it helped, mark it as brainliest.
Follow me to get the most simplified answers for your questions.
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