Question

two coins are tossed simultaneously what is the probability of getting at least one head?​

Answer 1

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E6 = {HT, TH, HH} and, therefore, n(E6) = 3. Therefore, P(getting at least 1 head) = P(E6) = n(E6)/n(S) = ¾.

Answer 2

Answer:

½

Step-by-step explanation:

the probability of getting head is ½ and of tail is also the same. if you add them they will be 1 (whole)

hope you understood